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Decomposition into weight × level + jump · conjecture survey

Decompwlj and the Great Conjectures

Where Legendre, Andrica, Cramér, the Riemann Hypothesis, twin primes, Goldbach and Collatz actually touch the coordinates a(n)=k(n)L(n)+d(n) — and where they only appear to.

Sources and corrections, before the results. (i) The project holds the treatise's tenth edition (19 Aug 2026), not the ninth named in the project brief; statuses below follow its §8 ledger, read through project search because the 2.6 MB file is only partly readable inline. (ii) Lemma 2's non-decomposable primes are {2,3,7}, not {2,3,5}: p=5 gives ℓ=3>2=g, while p=7 gives ℓ=3<4=g; recomputed here. (iii) The founding PDF and decompwlj_fordiv.txt are not in the current project file list; the kernels used are the project's own transcriptions of them.

A coordinate change cannot lower the difficulty of a classical problem. The useful question is therefore narrower than "does decompwlj prove X": it is whether a conjecture enters the framework as an input, an output, an exact restatement, or not at all, and whether anything new can be said at the point of contact. The survey found one genuinely structural contact point — a single inequality, ℓ≤d2, that converts gap conjectures into statements about the level class — and several honest null results.

ConjecturePoint of contact in decompwljKind of contactStatus
Bertrand / NaguraLemma 2: decomposable ⇔ a(n+1)<32a(n); on primes only {2,3,7} failproved inputproved
Legendreq(m)=nextprime(m2) is a valid input sequence ⇔ Legendre (§4)exact restatement of definabilityopen to 1.9·10⁹
Andrica, Oppermannforced-level set F={p:ℓ≤g2} (§2–3)too weak to decide Fopen
Cramér, Firoozbakhtsame set Feach implies F finite; Firoozbakht pins it to six primesconditional
Riemann Hypothesisvia Selberg's gap moment: #F(x)≪log3⁡x (§5)one-way, through gaps onlyconditional
Twin primes, Polignacweight-3 column (Lemma 4); gap columnsexact restatementopen
Hardy–Littlewoodhypothesis of Theorem 2 (level-one stratum, constant 2C2)conditional inputconditional
Balanced primescontained in Problem 2: is the level class infinite?native problem containing a classical oneopen
Goldbachabsent from the prime sequence (it sees only 2pn); present when N is decomposed against the primes above it: 2N=ℓj+qj (§7)exact restatement; 3/2 barrier = window (N/2,3N/2)open window to 10⁷
Collatzshared constant 3/2; every odd Collatz step is non-decomposable (§8)curiosity, no mechanismcuriosity

Two calibrations hold throughout. First, the framework's own native results — Theorem 1 proved* (level-classified density zero), Lemmas 1–5, Propositions 1–3, the column/lock structure — are unchanged by anything here. Second, Theorem 1's aggregate rarefaction is reproduced within about 1% by a Cramér random sequence of matching density (treatise §7), so it is not evidence of prime-specific structure and is not used below as such.

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The single contact point

When the gap alone decides the class

Classification compares k with L=ℓ/k, so a(n) is level-classified exactly when k>ℓ: when ℓ has no divisor in the window (d,ℓ]. If d≥ℓ the window is empty and arithmetic is never consulted.

Reading the (k, L) plane. Every figure in this report uses the coordinates (k,L): weight log10⁡k on the horizontal axis, level log10⁡L on the vertical axis, equal aspect. A decomposable term sits on its hyperbola kL=ℓ, a line of slope −1 in these axes. The diagonal k=L separates level-classified terms (below it, k>L) from weight-classified ones (above it). On the hyperbola the gate is the point (d, ℓ/d) where k=d; the weight is the first divisor of ℓ at or beyond the gate, so the term is reached by sliding down its hyperbola from the gate. When the gate already lies on or below the diagonal, the term is level whatever ℓ factors into. Colours are fixed throughout: level-classified terms in copper, weight-classified in indigo, the forced set F as dark open circles.

Proposition B · forced level proved

If a(n) is decomposable and ℓ(n)≤d(n)2, then a(n) is level-classified, with L(n)<d(n)<k(n).

Proof. k>d≥ℓ, hence L=ℓ/k<ℓ/d≤d<k. ∎ (Stated in earlier project reports as Proposition B; included so the page is self-contained.)

On the primes, write F={pn: gn<ℓ(n)≤gn2}, the forced set. Since ℓ=p−g, membership is the purely additive inequality g2+g≥p: a gap at least about p.

Computation + closure · the forced set below 4⋅1018 verified

F∩[1,4⋅1018)={5,13,19,23,31,113}.

Proof. Exhaustive check below 14762+1476=2,180,052 in PARI/GP, and independently in a NumPy sieve to 109 (no member above 113). For 2,180,052≤p<4⋅1018 every gap is at most 1476, the largest gap below 4⋅1018 in the tables of Oliveira e Silva, Herzog and Pardi, so g2+g≤1476⋅1477<p. ∎
pgℓg2kLℓ/g2
5234310.750
134916910.563
1941516530.938
23617361710.472
31625362510.694
11314991963330.505

These six primes already sit in the project's verification record as a closed exception set; what is added here is their reading as the complete list of primes whose class is decided by gap size alone. All six are level-classified, as Proposition B requires. Beyond 113 every level-classified prime is earned: ℓ had an open window and happened to have no divisor in it. Earlier atlas work found the same split across sequences — triangular numbers are 100% forced, the primes essentially 0%.

Equivalence · finiteness of F is a gap statement open

F is finite ⟺ gn2+gn<pn for all sufficiently large n ⟺ lim supngn/pn≤1 with strict inequality eventually.

This is an Andrica-type statement with constant 1 in place of 2. Unconditionally only the trivial bound is available: gaps longer than y/2 are disjoint, so #F∩[y,2y]≪y and #F(x)≪x. The best unconditional gap exponent, g≪p0.525 (Baker–Harman–Pintz), sits above p and decides nothing. The next page places every named gap conjecture against this threshold.

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Andrica, Oppermann, Cramér, Firoozbakht

The gap ladder, read against g2+g=p

Square log-log plot in (k, L) coordinates: gates of all maximal-gap primes up to 1.4e18 near the left edge along the Cramér curve, the Andrica bound just below the diagonal, and an inset with the six forced primes
Figure 1. The gap conjectures in (k,L) coordinates (log10⁡k across, log10⁡L up, equal aspect). Open circles: the gate (g, ℓ/g) of each of the 39 decomposable maximal-gap primes — computed here to 109, and from the published tables up to 1.4⋅1018, where the largest gap is 1476. Each is joined along its hyperbola to its actual decomposition (k,L): copper if level-classified (16 of the 39, all earned), indigo if weight-classified. Shaded: the level side k>L; a gate there means ℓ≤g2 and the term is forced level. Rose: the furthest gate Andrica's conjecture allows (k≲4L). Teal: the Cramér scale and the Firoozbakht–Kourbatov bound, along which real gates run, hugging the left edge. Inset: only the six primes of F ever have their gate on the level side.
ConjectureGap bound it givesvs. needed ≈pDecides F?
Baker–Harman–Pintz theoremg≪p0.525exponent too largeno
Legendreg<4p+4 (a prime in every (m2,(m+1)2))constant 4no
Oppermanng≤2p+O(1) (primes in (m2−m,m2), (m2,m2+m))constant 2no
Andricapn+1−pn<1⟺g<2p+1constant 2no
RH (Cramér 1920)g≪plog⁡pone log too manyno — but see §5
Cramérg=O(log2⁡p)far belowyes, F finite
Firoozbakhtg<log2⁡p−log⁡p−1, k>9 (Kourbatov)far belowyes, F = the six primes

The Firoozbakht line can be made exact. Under Kourbatov's bound B(p)=log2⁡p−log⁡p−1, a forced prime past p9=23 needs B(p)2+B(p)≥p, which fails for every p above roughly 3,200 (solved numerically here). The exhaustive list below that height is the six primes of page 2. So Firoozbakht's conjecture implies F={5,13,19,23,31,113} exactly — a clean conditional statement, but it adds nothing beyond the unconditional closure to 4⋅1018, because Firoozbakht is itself verified only that far.

The instructive line is Andrica's. Its observed maximum is 0.6709, at p=7 (recomputed to 107), so data sit comfortably inside it — yet Andrica as stated tolerates gaps up to 2p, twice what F can absorb. The forced set is thus a half-Andrica question: decompwlj supplies a natural reason to care about the constant in g≤cp, and fixes the critical value at c=1. That is a reformulation, not progress; it is reported because the threshold is canonical rather than chosen.

Conjecture F open · gn2+gn<pn for every pn>113. Equivalent to "F has no element above 113". Verified to 4⋅1018. Implied by Firoozbakht and (for large n) by Cramér; not implied by Andrica, Oppermann, Legendre or RH as far as is known.

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Bertrand → Nagura → Lemma 2 → Legendre

Legendre's conjecture as a definability condition

The decomposition exists iff a(n+1)<32a(n), and on the primes Lemma 2 is proved from Nagura's theorem (a prime in (x,65x] for x≥25). Bertrand's postulate (ratio 2) would not suffice; Nagura's ratio 6/5 does. Legendre's conjecture is the next rung down — an interval of length about 2x instead of x/5 — and it has an exact home in the framework, as the domain of the map.

Proposition L1 proved

Let q(m)=nextprime(m2). The sequence (q(m))m≥1 is strictly increasing — hence a legitimate input to the decomposition — if and only if Legendre's conjecture holds.

Proof. If (m2,(m+1)2) contains a prime then q(m)<(m+1)2<q(m+1). If it contains none, then, (m+1)2 being composite, q(m)=q(m+1). ∎
Proposition L2 proved

Write q(m)=m2+δm. If m≥5 and δm,δm+1≤m/2, then q(m) is decomposable and forced-level: ℓ≤d2, k>d≥32m+2.

Proof. Since 1≤δ≤m/2, d=2m+1+δm+1−δm∈[32m+2, 52m],ℓ=m2−2m−1+2δm−δm+1∈[m2−52m+1, m2−m−2]. Then ℓ>d⟺m2−5m+1>0, true for m≥5; and d2≥94m2>ℓ. Apply Proposition B. ∎

Corollary. Every term q(m) with 5≤m<1.9⋅109 is level-classified and forced. For 2952≤m<1.9⋅109 this follows from L2, since δm is bounded by the gap straddling m2, at most 1476 ≤m/2 below 4⋅1018. For m<2952 it is part of the direct computation below.

Legendre sequence, computedm≤105 (both engines)m≤107 (Python)
strictly increasing (Legendre holds)yesyes
non-decomposable indicesm=1,2,3,4m=1,2,3,4
decomposable / level / forced99,996 / 99,996 / 99,996all forced
weight-classified00
level one (L=1)7,477—
smallest margin d2/ℓ2.566 at m=23: q=541→577, d=36, ℓ=505
Square log-log plot in (k, L) coordinates of the Legendre sequence: all terms below the diagonal, gates on the line k = 4L, and the worked example m = 23
Figure 2. The Legendre sequence q(m), 5≤m≤105, in (k,L) coordinates (log10⁡k across, log10⁡L up, equal aspect). Read one term first: m=23 gives q=541 and next term 577, so d=36 and ℓ=505=5⋅101. Its hyperbola kL=505 is dotted; the gate (36, 505/36) is already on the level side of the diagonal; the first divisor of 505 beyond 36 is 101, so the term lands at (k,L)=(101,5). For every term d≈2m and ℓ≈m2, so all gates fall on the line k≈4L (black dots), and all 99,996 points are level-classified (copper); the weight side is empty. The horizontal lines at the bottom are L=1,3,5,… (ℓ is odd); L=1 holds 7,477 terms.

Verdict. Legendre's conjecture is equivalent to the decomposition being defined on q, and once defined the decomposition carries no arithmetic signal: ℓ/d2→1/4 exactly as for a(m)=m2, whose terms are all forced (ℓ=m2−2m−1<(2m+1)2). The framework restates Legendre cleanly and then, by its own geometry, has nothing to add.

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The Riemann Hypothesis

A one-way street through gap moments

Nothing in the framework bears on the zeros of ζ. The contact is indirect: RH controls prime gaps, and gaps control the forced set. Two classical consequences of RH matter.

Cramér (1920). RH implies gn≪pnlog⁡pn. Against the threshold g≈p this misses by one logarithm, so RH does not, by this route, make F finite.

Selberg (1943). RH implies

S(x)=∑pn+1≤xgn2pn+1≪log3⁡x.

A second-moment bound is exactly what a set defined by large gaps needs.

Proposition R conditional on RH

#{n: pn+1≤x, pn∈F}≤3S(x)≪log3⁡x.

Proof. For pn∈F, g2≥ℓ=p−g, and decomposability gives g<p/2, so pn+1=p+g≤3(p−g). Each such term therefore contributes g2/pn+1≥13 to S(x). ∎

So under RH the forced set is at most polylogarithmically sparse, against the unconditional ≪x. The statement is true and it is the only implication from RH into the framework found in this survey — but it is about gaps, not about decompwlj: any set defined by g≳p inherits the same bound.

xS(x)S/log2⁡xS/log3⁡x
10³30.620.6420.0929
10⁴58.730.6920.0752
10⁵96.420.7270.0632
10⁶144.270.7560.0547
10⁷202.520.7800.0484
10⁸270.840.7980.0433
10⁹349.550.8140.0393

Computed from all 50,847,534 primes below 109. The ratio to log2⁡x creeps upward and the ratio to log3⁡x falls, consistent with the conjectured order log2⁡x quoted in the literature on Selberg's theorem; seven decades cannot identify the order, and none is claimed.

What RH does not do here

Theorem 1 is unconditional: its proof is an upper-bound sieve plus gap telescoping, and RH supplies nothing it lacks. Problem 2 — is the level class infinite? — needs a lower bound for a pattern of consecutive primes, and contains the balanced-prime problem; I know of no route from RH to it. In the opposite direction, no statement about weights or levels implies anything about ζ: the decomposition reads one consecutive pair at a time, while RH is a statement about all primes at once, and the two meet only through moments of the gap sequence.

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Twin primes, Polignac, Hardy–Littlewood, balanced primes

Where the framework does carry arithmetic

Here the conjectures enter as exact restatements or as hypotheses, and the framework adds its own unconditional constants.

Lemma 4 · the twin column proved

For p>3: k(p)=3⟺g(p)=2.

Proof. If g=2, p≡2(mod3) (else p+2≡0), so 3∣ℓ=p−2, and 3 is the least divisor above 2. If k=3 then g<3, and odd primes have even gaps, so g=2. ∎ Below 107: 58,979 primes on each side, the same index set, 0 violations.

So the twin prime conjecture is literally "the weight-3 column is infinite" (founding Conjecture 1), and the Polignac family maps onto gap columns and lines (founding Conjectures 2, 3, 5, 6). These are dictionaries reformulation: no difficulty is removed.

Hardy–Littlewood as input. Theorem 2 conditional gives the asymptotic of the level-one stratum assuming a uniform Hardy–Littlewood k-tuple estimate and a Gallagher-type gap model; its density constant is 2C2=1.3203236316…, twice the twin-prime constant. Lemma 1 proved identifies that constant unconditionally, as the line average of the singular series S(0,g,2g). This is the framework's strongest arithmetic content: a conjecture goes in, and a constant that does not depend on the conjecture comes out.

Mod-3 rigidity (Proposition 2 proved): for decomposable p≥5, exactly one of 3∣g, 3∣ℓ holds. It retires founding Conjectures 7–8 as elementary.

Problem 2 · the remaining native question open

Is the level class infinite? Theorem 1 is compatible with finiteness. Balanced primes pn=12(pn−1+pn+1) have ℓ=pn−1 prime and lie on L=1; so infinitely many balanced primes would settle Problem 2, and by difficulty conservation Problem 2 should be at least as hard.

Below 107: 21,837 balanced primes, every one on L=1 and level-classified (Figure 3, rose). Note the asymmetry with §2: the level class beyond 113 is entirely earned, which is why Problem 2 is arithmetic rather than a gap question.

Square log-log plot in (k, L) coordinates of the primes below one million: the weight class above the diagonal with the twin column k = 3, the level class as horizontal lines at odd levels below it, balanced primes on L = 1 and the forced set circled
Figure 3. The primes below 106 (78,495 decomposable terms) in (k,L) coordinates, equal aspect. Below the diagonal the level class (copper) is a comb of horizontal lines L=1,3,5,…; balanced primes sit on L=1 (rose). Above it lies the weight class (indigo), whose leftmost column k=3 is exactly the lesser twin primes (teal, Lemma 4). The six forced primes are circled.

What survives the control

The control experiment shows that the aggregate level share is generic for a sequence of prime density. The finer structure is not: admissibility-matched controls from the atlas work, the exact constant 2C2, the congruence lock Pr[r∣ℓ|d=g]=1/(r−2) for odd primes r>g, and the weight columns are where the Hardy–Littlewood singular series becomes visible in decompwlj coordinates. Any future contact with a classical conjecture will come through this layer, not through the headline rarefaction.

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Goldbach · binary partitions

Goldbach lives one step outside the prime sequence

Decomposing the primes reads one consecutive pair at a time, and its only additive identity is ℓ(n)+pn+1=2pn. Applied to the primes, the framework therefore sees only the doubles 2pn, where Goldbach is trivial (pn+pn). That is the precise sense in which Goldbach is absent. But a Goldbach partition 2N=p1+p2 with p1<N<p2 is itself a three-term progression (p1,N,p2), and the decomposition can be applied to it directly: decompose N against each prime q1<q2<⋯ above it. With dj=qj−N,

ℓj=N−dj=2N−qj,2N=ℓj+qj,N=kjLj+dj.
Proposition G · Goldbach in decompwlj coordinates proved

(i) N is decomposable against qj iff qj<32N, i.e. iff the partner ℓj exceeds N/2.
(ii) If it is decomposable and ℓj is prime, then kj=ℓj and Lj=1: a Goldbach partition is a level-one decomposition.
(iii) If ℓj>dj2, conversely Lj=1 forces ℓj prime.

Proof. (i) ℓj>dj⟺2N−qj>qj−N. (ii) A prime ℓj>dj has no divisor in (dj,ℓj). (iii) If ℓj is composite with least prime factor r≤ℓj, then ℓj/r≥ℓj>dj is a divisor below ℓj, so Lj≥r>1. ∎

So the 3/2 barrier of Lemma 2 becomes a natural Goldbach window: partitions with N/2<p1<N<p2<32N are exactly the level-one decompositions of N with a prime partner, and the case N=pn, j=1 is Species I. Outside the window (p1≤N/2) the framework has nothing to say.

Measured for 8≤2N≤107Result
a partition inside the window (N/2,32N)every 2N except 14,22,38,86 (Python to 107; PARI/GP to 4⋅105)
nearest partition m∗(N)=min{m≥1:N±m prime}always found; max 1842 at N=4,895,789; m∗/log2⁡N≤8.64 for N≥103
depth D(N): index j of the first partner qjmax 124; D=1 for 21.7%, 17.4%, 14.4%, 12.8% of N in successive decades
depth-one share ×log⁡N1.75, 1.80, 1.82, 1.87 — drifting toward 2, the parity factor alone (ℓj is always odd); heuristic
Lj=1 reached at a composite ℓj before the partition415 values of N≤2⋅105, all in the forced zone ℓj≤dj2 where (iii) fails
prime centres N=pn with D=1 (= Species I)23,943 primes in [5,5⋅106], identical in both computations

Verdict. Goldbach is equivalent to: for every N≥4, some decomposition of N against a prime above it has a prime partner ℓj — level one in the window, by (ii). This is the classical "primes equidistant from N" form (OEIS A047160) written in weight–level coordinates, and it is a dictionary: the level-one event is primality of 2N−qj, so the binary lower-bound problem is untouched. What the coordinates add is structural: the window (N/2,32N) is the decomposition's own domain; Species I is its special case at prime centres; and the forced zone marks where "level one" and "prime partner" come apart. The window statement — every 2N≥88 has such a partition — is a slightly stronger Goldbach variant, verified here to 107; I have not found it stated in the literature and do not claim it is new.

Shared local factors, not a link. The Hardy–Littlewood series for Goldbach is S(2N)=2C2∏p∣N,p>2p−1p−2, so the product 2C2 that Lemma 1 extracts from S(0,g,2g) is also Goldbach's value at 2N=2r. Both come from the same factors 1−(p−1)−2; Theorem 2 is a ternary count at prime centres and implies nothing about r(2N).

\\ Goldbach depth of N (uses decomp_fact from page 8): [m*, j, first j with L_j = 1, inside window?]
gb(N) = { my(q = N, j = 0, r, l, f = 0);
  while (1, q = nextprime(q+1); j++; l = 2*N - q; if (l < 2, return([-1, j, f, 0]));
    r = decomp_fact(N, q); if (r[1] && r[2] == 1 && !f, f = j);
    if (isprime(l), return([q - N, j, f, r[1] > 0]))) };
\\ gb(43) = [24, 5, 3, 0]: 86 = 19 + 67 lies outside the window, and L_3 = 1 at a composite l_3
\\ gb(4895789) = [1842, 124, 124, 1]
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Collatz, and the ledger

The other three-halves

The constant 3/2 appears in both theories for unrelated reasons. In decompwlj it comes from ℓ>d⟺a(n)>2d(n)⟺a(n+1)<32a(n). In Collatz it is the odd step T(x)=(3x+1)/2. One exact statement connects them, and it is a curiosity.

Proposition C proved curiosity

If x is odd and the next term of an increasing sequence is T(x), the term x is not decomposable. In particular every rising step of a Collatz trajectory is a non-decomposable pair.

Proof. T(x)=32x+12>32x; apply Lemma 2. ∎ The ramp from 240−1 makes 40 consecutive odd steps; all 40 pairs are non-decomposable (PARI/GP).
Collatz record sequence, terms <107pairsnon-decomposablelevelweightforced
delay records, A006877 (54 terms)531142038
path records, A006884 (38 terms)371423023

Both record sequences start as listed in the OEIS (1, 2, 3, 6, 7, 9, 18, 25, 27, … and 1, 2, 3, 7, 15, 27, 255, 447, …). They are sparse, so Proposition B makes most of them level by geometry alone — the same behaviour as any sequence growing at a fixed ratio. Nothing Collatz-specific is visible.

A Collatz-shaped iteration that is easy. The map p↦ℓ(p)=2p−nextprime(p), continued while the value stays prime, is the framework's own dynamics. Below 106 its chain lengths are 0 (72,544 primes), 1 (5,453), 2 (475) and 3 (24); the longest is 6397→6373→6367→6361. Every chain terminates because the map strictly decreases. Collatz is hard because T is not monotone; the decomposition's maps are, and that difference is why no technique transfers in either direction.

What this report adds

One canonical threshold (ℓ≤d2) through which gap conjectures act on the classification; the forced set F closed to 4⋅1018 and Conjecture F; Proposition R under RH; Propositions L1–L2 placing Legendre at the domain of the map; Proposition G and the Goldbach window (N/2,32N); Proposition C. All are restatements, one-way implications or elementary facts — the summary table on page 1 is the ledger. None changes the status of Theorem 1, Theorem 2 or Problem 2.

Compute it yourself (PARI/GP 2.15.4, as run)

\\ decompwlj x conjectures, PARI/GP 2.15.4. decomp_fact = project kernel (treatise §9), reflowed.
decomp_fact(n, n1) = { my(d = n1-n, l = n-d, D); if (l <= d, return([0,0,d]));
  D = divisors(l); for (i = 1, #D, if (D[i] > d, return([D[i], l/D[i], d]))) };
\\ forced-level primes (l <= g^2): exhaustive below 1476^2+1476; beyond, OeS-H-P gap tables close F
forced(X) = { my(F = List()); forprime(p = 5, X, my(g = nextprime(p+1)-p, l = p-g);
  if (l > g && l <= g^2, listput(F, p))); Vec(F) };
\\ Legendre sequence q(m) = nextprime(m^2): [M, increasing?, decomposable, level, forced, L=1]
legendre(M) = { my(q0 = 2, q1, r, s = [M,1,0,0,0,0]); for (m = 1, M, q1 = nextprime((m+1)^2);
  if (q1 <= q0, s[2] = 0); r = decomp_fact(q0, q1);
  if (r[1], s[3]++; if (r[1] > r[2], s[4]++); if (q0-r[3] <= r[3]^2, s[5]++); if (r[2] == 1, s[6]++));
  q0 = q1); s };
print(forced(1476^2 + 1476));   \\ [5, 13, 19, 23, 31, 113]
print(legendre(10^5));          \\ [100000, 1, 99996, 99996, 99996, 7477]

Expected output in the comments. The longer check file run this session also reproduces the census below 106 ([78495, 18353, 5953, 12], 0 disagreements between decomp_fact and decomp_fordiv) and the 40/40 Collatz ramp; the Python engine reproduces the census rows to 107 (664,576 / 138,049 / 44,011 / 28), the forced set to 109 and the Legendre census.

References

  1. R. Eismann, founding paper, arXiv:0711.0865; treatise, 10th ed. (project document, 19 Aug 2026).
  2. T. Oliveira e Silva, S. Herzog, S. Pardi, Empirical verification of the even Goldbach conjecture and computation of prime gaps up to 4·10¹⁸, Math. Comp. 83 (2014). Maximal gaps also from the table of known maximal gaps.
  3. A. Selberg, On the normal density of primes in small intervals, and the difference between consecutive primes, Arch. Math. Naturvid. 47 (1943); exposition in arXiv:1802.07609; see also Erdős problem 233.
  4. H. Cramér, Some theorems concerning prime numbers, Ark. Mat. Astr. Fys. 15 (1920); On the order of magnitude of the difference between consecutive prime numbers, Acta Arith. 2 (1936).
  5. A. Kourbatov, Upper bounds for prime gaps related to Firoozbakht's conjecture, J. Integer Seq. 18 (2015), 15.11.2.
  6. R. C. Baker, G. Harman, J. Pintz, The difference between consecutive primes II, Proc. LMS 83 (2001). J. Nagura, On the interval containing at least one prime number, Proc. Japan Acad. 28 (1952).
  7. OEIS A117078, A117563, A118534, A001223, A002386, A006562, A006877, A006884.